ram: Refactor Linux perc/used
Fixes up overly complicated line, by splitting up logic
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@ -27,6 +27,7 @@
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ram_perc(const char *unused)
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{
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uintmax_t total, free, buffers, cached;
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int percent;
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if (pscanf("/proc/meminfo",
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"MemTotal: %ju kB\n"
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@ -42,8 +43,8 @@
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return NULL;
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}
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return bprintf("%d", 100 * ((total - free) - (buffers + cached))
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/ total);
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percent = 100 * ((total - free) - (buffers + cached)) / total;
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return bprintf("%d", percent);
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}
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const char *
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@ -62,7 +63,7 @@
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const char *
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ram_used(const char *unused)
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{
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uintmax_t total, free, buffers, cached;
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uintmax_t total, free, buffers, cached, used;
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if (pscanf("/proc/meminfo",
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"MemTotal: %ju kB\n"
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@ -70,12 +71,11 @@
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"MemAvailable: %ju kB\n"
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"Buffers: %ju kB\n"
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"Cached: %ju kB\n",
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&total, &free, &buffers, &buffers, &cached) != 5) {
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&total, &free, &buffers, &buffers, &cached) != 5)
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return NULL;
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}
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return fmt_human((total - free - buffers - cached) * 1024,
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1024);
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used = (total - free - buffers - cached);
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return fmt_human(used * 1024, 1024);
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}
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#elif defined(__OpenBSD__)
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#include <stdlib.h>
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