Print unknown_str in case of error
func can return NULL in case of error, but no checking is done when printing, and unknown_str wasn't being used anywhere.
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@ -87,8 +87,10 @@ main(int argc, char *argv[])
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status[0] = '\0';
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for (i = len = 0; i < LEN(args); i++) {
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const char * res = args[i].func(args[i].args);
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res = (res == NULL) ? unknown_str : res;
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len += snprintf(status + len, sizeof(status) - len,
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args[i].fmt, args[i].func(args[i].args));
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args[i].fmt, res);
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if (len >= sizeof(status)) {
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status[sizeof(status) - 1] = '\0';
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